Next breakthroughs by forming Cycle (8,9) in R7C, R7C9 by DSA reduction in both cases by from possible digit subset in four empty cells of R7.Ĭycle reduces possible digit subset for R7C4, R7C6 to and with in C6 we get the breakthrough R7C5 5 by reduction of 7 followed by R7C4 7 by exception. Next R1C8 7 by scan for 7 in R2, R3, C9 and that's all by row column scan at this point.īut by DSA we get the valid cell, R8C2 9 by reduction of from bottom left major square DS - R8C3 1 by reduction of in R8 from DS in bottom left major square. This is a breakthrough that otherwise couldn't have been achieved. This lock on C9 immediately participates in a row column scan for 3 in R7, lock in R9, 3 in C5 and 3 in C6 to produce unique digit 3 in cell R8C4 - R8C4 3. Though number of digit 3 is small, we identify first a single digit lock for 3 in R9C7, R9C9 by cross scan for 3 in R7, C8. Starting the solution process, first valid cell success by row column is for 2: R8C7 2 by scan for 2 in R9, C8, C9 - R7C1 2 by scan for 2 in R8, R9. Otherwise we know that the single digit lock might become useful later and we ignore it for the present. If we get one, we should get usually a breakthrough in one step or two. In the process we may get valid cells, but otherwise our lookout is for identifying for a single digit lock by cross scan.
Strategy adopted: start with row column scan coupled with aggressive breakthroughs by advanced Sudoku techniques.Īs a strategy we always start row column scan from digit 1 and continue till digit 9. Step by step solution to the NY Times Sudoku Hard 4th March, 2021 Stage 1: Breakthrough by Single digit lock, Parallel digit scan, DSA and Cycles The NY Times Sudoku hard 4th March 2021īefore going through the solution solve the puzzle first. The NY Times Sudoku Hard 4th March 2021 solved step by step quickly and easily by advanced Sudoku techniques with breakthroughs explained adequately.
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How to solve NY Times Sudoku Hard Maby advanced Sudoku techniques
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